SOLVED: tan x=- 4 /3 , pi 2 < alpha< pi; cos beta= sqrt 3/ 2 ,0< beta< pi 2
=\frac{\sqrt{2}}{2}&line2=\mathrm{Solution:\:}x=\frac{%CF%80}{6}%2B\frac{2%CF%80n}{3},x=\frac{2%CF%80n}{3}%2B\frac{%CF%80}{3} "sin(3x-pi/4)=(sqrt(2))/2")
sin(3x-pi/4)=(sqrt(2))/2
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How to integrate [math]\dfrac {3x^3-x^2+2x-4} {\sqrt {x^2-3x+2}} dx[/math] - Quora
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If x=3 square root of 5 then the value of square root of x/2 +whole square root of 3x 2 will be equal to
SOLUTION: Find the domain and range of the following function in interval form. f(x)= {{{ sqrt( x^2+3x-4 ) }}}* {{{ sqrt( 2-x-x^2 ) }}}
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Ex 3.3, 11 - Prove that cos (3pi/4 + x) - cos (3pi/4 - x)
