![Using integral int 0^pi/2 (sinx) dx = int 0^pi/2 (secx) dx = - pi2 2 Evaluate int -pi/4^pi/4 (sinx+cosxcosx-sinx)dx = Using integral int 0^pi/2 (sinx) dx = int 0^pi/2 (secx) dx = - pi2 2 Evaluate int -pi/4^pi/4 (sinx+cosxcosx-sinx)dx =](https://haygot.s3.amazonaws.com/questions/2022264_1093019_ans_dffa6517e3c2470cba94d8e617d82ffa.jpg)
Using integral int 0^pi/2 (sinx) dx = int 0^pi/2 (secx) dx = - pi2 2 Evaluate int -pi/4^pi/4 (sinx+cosxcosx-sinx)dx =
![Given that integral of (sinx)/x= pi/2 (limit= 0 to infinity) Then prove that integral of ((sin x)^3)/x = - Maths - Integrals - 14533001 | Meritnation.com Given that integral of (sinx)/x= pi/2 (limit= 0 to infinity) Then prove that integral of ((sin x)^3)/x = - Maths - Integrals - 14533001 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_5eb96d2e2b243.jpg)
Given that integral of (sinx)/x= pi/2 (limit= 0 to infinity) Then prove that integral of ((sin x)^3)/x = - Maths - Integrals - 14533001 | Meritnation.com
![Consider the integral int_{0}^{pi / 2} sqrt{sin x} dx. Write an expression that approximates the integral, with n = 6, and evaluate that expression, using the indicated method. Use the Trapezoidal Rul Consider the integral int_{0}^{pi / 2} sqrt{sin x} dx. Write an expression that approximates the integral, with n = 6, and evaluate that expression, using the indicated method. Use the Trapezoidal Rul](https://homework.study.com/cimages/multimages/16/image155801295188063436580.png)
Consider the integral int_{0}^{pi / 2} sqrt{sin x} dx. Write an expression that approximates the integral, with n = 6, and evaluate that expression, using the indicated method. Use the Trapezoidal Rul
![calculus - Difficulties understanding a proof of $\int_0^{\infty} \frac{\sin (x)}{x} \, dx = \frac{\pi}{2}$ - Mathematics Stack Exchange calculus - Difficulties understanding a proof of $\int_0^{\infty} \frac{\sin (x)}{x} \, dx = \frac{\pi}{2}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/RUp17.png)