![SOLVED: Can provide clear codes and how look the graph?? Given a DTMF transmission signal y= A sin(2pi f t)+ A sin(2pi f t) where the 1122 frequency of the signals will SOLVED: Can provide clear codes and how look the graph?? Given a DTMF transmission signal y= A sin(2pi f t)+ A sin(2pi f t) where the 1122 frequency of the signals will](https://cdn.numerade.com/ask_images/89ff0caaba2f437fade4885e73667a55.jpg)
SOLVED: Can provide clear codes and how look the graph?? Given a DTMF transmission signal y= A sin(2pi f t)+ A sin(2pi f t) where the 1122 frequency of the signals will
How does the term sin (2*pi*f*t) come from? I know that sin and cosine take radians as arguments which will be (pi/2) * (no. of degrees) but why do we mulitply f*t?
How does the term sin (2*pi*f*t) come from? I know that sin and cosine take radians as arguments which will be (pi/2) * (no. of degrees) but why do we mulitply f*t?
![Given that : ` y = A sin [(( 2 pi)/( lambda)) ( c t - x) ]` , where y and x are measured in the ... - YouTube Given that : ` y = A sin [(( 2 pi)/( lambda)) ( c t - x) ]` , where y and x are measured in the ... - YouTube](https://i.ytimg.com/vi/iOC_vjUazSw/maxresdefault.jpg)
Given that : ` y = A sin [(( 2 pi)/( lambda)) ( c t - x) ]` , where y and x are measured in the ... - YouTube
![A sinusoidal wave `y=a sin ((2pi)/lambda x-omegat)` is travelling on a stretched string. An - YouTube A sinusoidal wave `y=a sin ((2pi)/lambda x-omegat)` is travelling on a stretched string. An - YouTube](https://i.ytimg.com/vi/mYlKR9tz29M/maxresdefault.jpg)
A sinusoidal wave `y=a sin ((2pi)/lambda x-omegat)` is travelling on a stretched string. An - YouTube
![SOLVED:At time t=0 a high amplitude signal has a profile y=a sinπx with ∂y / ∂t=0 . Thereafter, it propagates according to the non-linear wave equation (∂^2 y)/(∂t^2)=c0^2(1+ε(∂y)/(∂x)) (∂^2 y)/(∂x^2) where εis SOLVED:At time t=0 a high amplitude signal has a profile y=a sinπx with ∂y / ∂t=0 . Thereafter, it propagates according to the non-linear wave equation (∂^2 y)/(∂t^2)=c0^2(1+ε(∂y)/(∂x)) (∂^2 y)/(∂x^2) where εis](https://cdn.numerade.com/previews/75f7b1c3-3779-445c-8c7f-087654c3e6ed.gif)
SOLVED:At time t=0 a high amplitude signal has a profile y=a sinπx with ∂y / ∂t=0 . Thereafter, it propagates according to the non-linear wave equation (∂^2 y)/(∂t^2)=c0^2(1+ε(∂y)/(∂x)) (∂^2 y)/(∂x^2) where εis
![A transverse wave is described by the equation y = y0sin 2pi ( ft - xlambda ) . The maximum particle velocity is equal to four times the wave velocity if A transverse wave is described by the equation y = y0sin 2pi ( ft - xlambda ) . The maximum particle velocity is equal to four times the wave velocity if](https://dwes9vv9u0550.cloudfront.net/images/3501081/d994a3de-f94c-4a30-b5b3-496a5dece602.jpg)